Need help driving MOSFET

[Dolci]

My favorite.. isolated Mosfet Gate Driver Paper

https://grobotronics.com/mosfet-control-module-100v-9-4a-fr120n.html?sl=en&srsltid=AfmBOorXsKnPIG2J50TUt1wFq48gg63CvW-wGAmDKeExhCB_23TR9OSe

[Fanie]

Let\s hear from JohnB if he solved his problem...

[streborc]

MOSFETs can be a bit tricky to work with, but once you understand the basics and use them in a couple applications, you'll find them preferable to BJTs because MOSFETs behave more like real switches -- either on or off.  Driving a 5 volt device through a MOSFET with a 5 volt PIC isn't too difficult, unless switching speed is critical.  Driving a high voltage device (let's say 12 volts) from a 5 volt PIC can most easily be accomplished with a MOSFET driver device, such as the MCP1405 which provides both the necessary MOSFET gate current and level conversion.  I've successfully used the MCP1405 with an FDD8424H complementary MOSFET to control a 12 volt solenoid in a hydraulic actuator application.  This was a quasi-static switching application, not a continuous frequency application where shoot-thru current becomes a concern.  If you're switching continuous frequency, you should look into using the complementary waveform generator (CWG) featured in many PICs that provides a dead-zone so that the N-channel and P-channel devices are not simultaneously on.  Finally, if you're using a PIC in a 3.3 volt application (I'm working on an infrared remote control where the IR emitter is switched with a 3.3 volt MOSFET) you need to use a low voltage MOSFET such as the FDV303N that has a Rds(on) = 0.6R at Vgs = 2.7 volts.  There's quite a bit of MOSFET application note info online that explains all this is as much detail as you want to dive into.  Hope this helps.

[JohnB]

Solved and this is my schematic.  Outlined area is place bit in question. 

[Fanie]

Hi John, the two resistors R10 and R11 is now a voltage divider with R9 and R7.
This means the FETs will only get 2V5 on the gate.  Measure it.
I suggest remove R10 and R11 so the FETs are switched with 5V on the gate.
A 1k resistor with 5V will draw 5mA, you need only around 1 or 2mA, unless you have some extreme induction problems.

[JohnB]

The resistor values are the defaults that EasyPC use and I was too lazy to change them on the CCT.
The values were 100 and 10K. Apologies for the confusion.